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Exercises Numbers, fractions and percents

Example 1.49 from Prealgebra, 1.4 Multiply Whole Numbers

Multiply Whole Numbers: example 1.49

Multiply: $(896) 201 .$

Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.

Solution
There should be $3$ partial products. The second partial product will be the result of multiplying $896$ by $0 .$

Notice that the second partial product of all zeros doesn’t really affect the result. We can place a zero as a placeholder in the tens place and then proceed directly to multiplying by the $2$ in the hundreds place, as shown.

Multiply by $10,$ but insert only one zero as a placeholder in the tens place. Multiply by $200,$ putting the $2$ from the $12 .$ $2 \cdot 6 = 12$ in the hundreds place.

$\begin{matrix} 896 \\ \underset{_____}{\times 201} \\ 896 \\ \underset{__________}{17920} \\ 180,096 \end{matrix}$

Your turn

The book's Try It right after this example: same idea, new numbers. Only the answer is given.

Multiply: $(718) 509 .$

How did it go?

PreviousMultiply Whole Numbers: example 1.48 Next Multiply Whole Numbers: example 1.50

From Prealgebra (1st edition) by OpenStax (Rice University), section 1.4, licensed under CC BY 4.0. Original at openstax.org. We split the solution into steps; the words, numbers and figures are the book's. OpenStax doesn't endorse this site.