Example 6.3 from College Physics, 6.2 Centripetal Acceleration
Calculate the centripetal acceleration of a point 7.50 cm from the axis of an ultracentrifuge spinning at Determine the ratio of this acceleration to that due to gravity. See Figure 6.9(b).
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
The term rev/min stands for revolutions per minute. By converting this to radians per second, we obtain the angular velocity . Because is given, we can use the second expression in the equation to calculate the centripetal acceleration.
To convert to radians per second, we use the facts that one revolution is and one minute is 60.0 s. Thus,
Now the centripetal acceleration is given by the second expression in as
Converting 7.50 cm to meters and substituting known values gives
Note that the unitless radians are discarded in order to get the correct units for centripetal acceleration. Taking the ratio of to yields
This last result means that the centripetal acceleration is 472,000 times as strong as . It is no wonder that such high centrifuges are called ultracentrifuges. The extremely large accelerations involved greatly decrease the time needed to cause the sedimentation of blood cells or other materials.
How did it go?