Example 19.9 from College Physics, 19.6 Capacitors in Series and Parallel
Find the total capacitance for three capacitors connected in series, given their individual capacitances are 1.000, 5.000, and 8.000 .
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
With the given information, the total capacitance can be found using the equation for capacitance in series.
Entering the given capacitances into the expression for gives .
Inverting to find yields .
The total series capacitance is less than the smallest individual capacitance, as promised. In series connections of capacitors, the sum is less than the parts. In fact, it is less than any individual. Note that it is sometimes possible, and more convenient, to solve an equation like the above by finding the least common denominator, which in this case (showing only whole-number calculations) is 40. Thus,
so that
How did it go?