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Example 11.5 from College Physics, 11.4 Variation of Pressure with Depth in a Fluid
Calculate the depth below the surface of water at which the pressure due to the weight of the water equals 1.00 atm.
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
We begin by solving the equation for depth :
Then we take to be 1.00 atm and to be the density of the water that creates the pressure.
Entering the known values into the expression for gives
Just 10.3 m of water creates the same pressure as 120 km of air. Since water is nearly incompressible, we can neglect any change in its density over this depth.
How did it go?