Example 12 from Algebra and Trigonometry, 4.1 Linear Functions
Graph using the y-intercept and slope.
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
Evaluate the function at to find the y-intercept. The output value when is 5, so the graph will cross the y-axis at
According to the equation for the function, the slope of the line is This tells us that for each vertical decrease in the “rise” of units, the “run” increases by 3 units in the horizontal direction. We can now graph the function by first plotting the y-intercept on the graph in Figure 13. From the initial value we move down 2 units and to the right 3 units. We can extend the line to the left and right by repeating, and then drawing a line through the points.
The book's Try It right after this example: same idea, new numbers. Only the answer is given.
Find a point on the graph we drew in Example 12 that has a negative x-value.
How did it go?