Use the Rectangular Coordinate System: example 11.6

Point A is above $\mathrm{-3}$ on the $x\text{-axis},$ so the $x\text{-coordinate}$ of the point is $\mathrm{-3}.$ The point is to the left of $3$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $3.$ The coordinates of the point are $\left(\mathrm{-3},3\right).$

Point B is below $\mathrm{-1}$ on the $x\text{-axis},$ so the $x\text{-coordinate}$ of the point is $\mathrm{-1}.$ The point is to the left of $\mathrm{-3}$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $\mathrm{-3}.$ The coordinates of the point are $\left(\mathrm{-1},\mathrm{-3}\right).$

Point C is above $2$ on the $x\text{-axis},$ so the $x\text{-coordinate}$ of the point is $2.$ The point is to the right of $4$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $4.$ The coordinates of the point are $\left(2,4\right).$

Point D is below $4$ on the $x-\text{axis},$ so the $x\text{-coordinate}$ of the point is $4.$ The point is to the right of $\mathrm{-4}$ on the $y\text{-axis},$ so the $y\text{-coordinate}$ of the point is $\mathrm{-4}.$ The coordinates of the point are $\left(4,\mathrm{-4}\right).$