Example 24.3 from College Physics, 24.3 The Electromagnetic Spectrum
During laser vision correction, a brief burst of 193-nm ultraviolet light is projected onto the cornea of a patient. It makes a spot 0.80 mm in diameter and evaporates a layer of cornea thick. Calculate the energy absorbed, assuming the corneal tissue has the same properties as water; it is initially at . Assume the evaporated tissue leaves at a temperature of .
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
The energy from the laser light goes toward raising the temperature of the tissue and also toward evaporating it. Thus we have two amounts of heat to add together. Also, we need to find the mass of corneal tissue involved.
To figure out the heat required to raise the temperature of the tissue to , we can apply concepts of thermal energy. We know that
where Q is the heat required to raise the temperature, is the desired change in temperature, is the mass of tissue to be heated, and is the specific heat of water equal to 4186 J/kg/K.
Without knowing the mass at this point, we have
The latent heat of vaporization of water is 2256 kJ/kg, so that the energy needed to evaporate mass is
To find the mass , we use the equation , where is the density of the tissue and is its volume. For this case,
Therefore, the total energy absorbed by the tissue in the eye is the sum of and :
The lasers used for this eye surgery are excimer lasers, whose light is well absorbed by biological tissue. They evaporate rather than burn the tissue, and can be used for precision work. Most lasers used for this type of eye surgery have an average power rating of about one watt. For our example, if we assume that each laser burst from this pulsed laser lasts for 10 ns, and there are 400 bursts per second, then the average power is .
How did it go?