Example 25.2 from College Physics, 25.3 The Law of Refraction
Find the index of refraction for medium 2 in Figure 25.12(a), assuming medium 1 is air and given the incident angle is and the angle of refraction is .
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
The index of refraction for air is taken to be 1 in most cases (and up to four significant figures, it is 1.000). Thus here. From the given information, and . With this information, the only unknown in Snell’s law is , so that it can be used to find this unknown.
Snell’s law is
Rearranging to isolate gives
Entering known values,
This is the index of refraction for water, and Snell could have determined it by measuring the angles and performing this calculation. He would then have found 1.33 to be the appropriate index of refraction for water in all other situations, such as when a ray passes from water to glass. Today we can verify that the index of refraction is related to the speed of light in a medium by measuring that speed directly.
How did it go?