Example 27.1 from College Physics, 27.3 Young’s Double Slit Experiment
Suppose you pass light from a He-Ne laser through two slits separated by 0.0100 mm and find that the third bright line on a screen is formed at an angle of relative to the incident beam. What is the wavelength of the light?
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
The third bright line is due to third-order constructive interference, which means that . We are given and . The wavelength can thus be found using the equation for constructive interference.
The equation is . Solving for the wavelength gives
Substituting known values yields
To three digits, this is the wavelength of light emitted by the common He-Ne laser. Not by coincidence, this red color is similar to that emitted by neon lights. More important, however, is the fact that interference patterns can be used to measure wavelength. Young did this for visible wavelengths. This analytical technique is still widely used to measure electromagnetic spectra. For a given order, the angle for constructive interference increases with , so that spectra (measurements of intensity versus wavelength) can be obtained.
How did it go?