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Exercises Magnetism and induction

Example 22.4 from College Physics, 22.7 Magnetic Force on a Current-Carrying Conductor

Calculating Magnetic Force on a Current-Carrying Wire: A Strong Magnetic Field

Calculate the force on the wire shown in Figure 22.30, given $B = 1 . 50 T$ , $l = 5 . 00 cm$ , and $I = 20 . 0 A$ .

Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.

Strategy
The force can be found with the given information by using $F = IlB sin θ$ and noting that the angle $θ$ between $I$ and $B$ is $90º$ , so that $sin θ = 1$ .
Solution
Entering the given values into $F = IlB sin θ$ yields
$F = IlB sin θ = (20 .0 A) (0 . 0500 m) (1 . 50 T) (1) .$
22.17

The units for tesla are $1 T = \frac{N}{A \cdot m}$ ; thus,
$F = 1 . 50 N.$
22.18
Discussion
This large magnetic field creates a significant force on a small length of wire.

0 of 3 steps open

How did it go?

PreviousCalculating the Hall emf: Hall Effect for Blood Flow Next Calculating Torque on a Current-Carrying Loop in a Strong Magnetic Field

From College Physics (1st edition) by OpenStax (Rice University), section 22.7, licensed under CC BY 4.0. Original at openstax.org. We split the solution into steps; the words, numbers and figures are the book's. OpenStax doesn't endorse this site.