Example 23.13 from College Physics, 23.12 RLC Series AC Circuits
For the same RLC series circuit having a resistor, a 3.00 mH inductor, and a capacitor: (a) Find the resonant frequency. (b) Calculate at resonance if is 120 V.
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
The resonant frequency is found by using the expression in . The current at that frequency is the same as if the resistor alone were in the circuit.
Entering the given values for and into the expression given for in yields
We see that the resonant frequency is between 60.0 Hz and 10.0 kHz, the two frequencies chosen in earlier examples. This was to be expected, since the capacitor dominated at the low frequency and the inductor dominated at the high frequency. Their effects are the same at this intermediate frequency.
The current is given by Ohm’s law. At resonance, the two reactances are equal and cancel, so that the impedance equals the resistance alone. Thus,
At resonance, the current is greater than at the higher and lower frequencies considered for the same circuit in the preceding example.
How did it go?