Contingency Tables: example 3.23

a. $\frac{\text{133}\text{.1}}{\text{4,520}\text{.7}}$ = .0294, b. $\frac{\text{701}}{\text{4,520}\text{.7}}$ = .1551, c. P(2010 OR Crime B) = P(2010) + P(Crime B) – P(2010 AND Crime B) = $\frac{\text{1,087}\text{.1}}{\text{4,520}\text{.7}}$ + $\frac{\text{2,852}\text{.9}}{\text{4,520}\text{.7}}$ − $\frac{\text{701}}{\text{4,520}\text{.7}}$ = .7165, d. $\frac{\text{113}\text{.7}}{\text{511}\text{.8}}$ = .2222, e. $\frac{\text{314}\text{.7}}{\text{1,222}\text{.2}}$ = .2575