Tree and Venn Diagrams: example 3.26

Which shows the probability that both kittens are tabby?

$a. (\frac{1}{2}) (\frac{1}{2})$ $b. (\frac{4}{9}) (\frac{4}{9})$ $c. (\frac{4}{9}) (\frac{3}{8})$ $d. (\frac{4}{9}) (\frac{5}{9})$
What is the probability that one kitten of each coloring is selected?

$a. (\frac{4}{9}) (\frac{5}{9})$ $b. (\frac{4}{9}) (\frac{5}{8})$ $c. (\frac{4}{9}) (\frac{5}{9}) + (\frac{5}{9}) (\frac{4}{9})$ $d. (\frac{4}{9}) (\frac{5}{8}) + (\frac{5}{9}) (\frac{4}{8})$
What is the probability that a tabby is chosen as the second kitten when a black kitten was chosen as the first?
What is the probability of choosing two kittens of the same color?

Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.

Solution
a. $(\frac{4}{9}) (\frac{3}{8})$ , b. $(\frac{4}{9}) (\frac{5}{8}) + (\frac{5}{9}) (\frac{4}{8})$ , c. $\frac{4}{8}$ , d. $\frac{32}{72}$

How did it go?