(part 2)

b. You can use the tree diagram. There are nine ways to draw two reds and 121 possible outcomes. So, P(RR) = $\frac{\text{9}}{\text{121}\text{.}}$.

Each draw is independent, so you can also use the formula: P(RR) = P(R)P(R) = $\left(\frac{3}{11}\right)\left(\frac{3}{11}\right)$ = $\frac{9}{121\text{.}}$