Example 4.2 from Statistics, 4.1 Probability Distribution Function (PDF) for a Discrete Random Variable

(part 3)

c. Suppose one week is randomly chosen. Construct a probability distribution table (called a PDF table) like the one in Example 4.1. The table should have two columns labeled x and P(x).

Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.

Solution
c.

x P(x)

0 .01

1 .04

2 .15

3 .80

Table 4.4

The sum of the P(x) column is 0.01+0.04+0.15+0.80 = 1.00.

x	P(x)
0	.01
1	.04
2	.15
3	.80

How did it go?

Solution

Solution