Example 3 from Algebra and Trigonometry, 11.6 Solving Systems with Gaussian Elimination
Solve the given system by Gaussian elimination.
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
First, we write this as an augmented matrix.
We want a 1 in row 1, column 1. This can be accomplished by interchanging row 1 and row 2.
We now have a 1 as the first entry in row 1, column 1. Now let’s obtain a 0 in row 2, column 1. This can be accomplished by multiplying row 1 by and then adding the result to row 2.
We only have one more step, to multiply row 2 by
Use back-substitution. The second row of the matrix represents Back-substitute into the first equation.
The solution is the point
The book's Try It right after this example: same idea, new numbers. Only the answer is given.
Solve the given system by Gaussian elimination.
How did it go?