Example 5.24 from Elementary Algebra, 5.2 Solve Systems of Equations by Substitution
Heather has been offered two options for her salary as a trainer at the gym. Option A would pay her $25,000 plus $15 for each training session. Option B would pay her $10,000 + $40 for each training session. How many training sessions would make the salary options equal?
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
| Step 1. Read the problem. | |
| Step 2. Identify what you are looking for. | We are looking for the number of training sessions that would make the pay equal. |
| Step 3. Name what we are looking for. | Let Heather’s salary. the number of training sessions |
| Step 4. Translate into a system of equations. | Option A would pay her $25,000 plus $15 for each training session. |
| Option B would pay her $10,000 + $40 for each training session |
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| The system is: | |
| Step 5. Solve the system of equations. We will use substitution. |
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| Substitute 25,000 + 15n for s in the second equation. | |
| Solve for n. | |
| Step 6. Check the answer. | Are 600 training sessions a year reasonable? Are the two options equal when n = 600? |
| Step 7. Answer the question. | The salary options would be equal for 600 training sessions. |
The book's Try It right after this example: same idea, new numbers. Only the answer is given.
Geraldine has been offered positions by two insurance companies. The first company pays a salary of $12,000 plus a commission of $100 for each policy sold. The second pays a salary of $20,000 plus a commission of $50 for each policy sold. How many policies would need to be sold to make the total pay the same?
How did it go?