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Example 3.11 from Elementary Algebra, 3.1 Use a Problem-Solving Strategy
A married couple together earns $110,000 a year. The wife earns $16,000 less than twice what her husband earns. What does the husband earn?
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
| Step 1. Read the problem. | ||
| Step 2. Identify what we are looking for. | How much does the husband earn? | |
| Step 3. Name. | ||
| Choose a variable to represent the amount the husband earns. | Let the amount the husband earns. | |
| The wife earns $16,000 less than twice that. | the amount the wife earns. | |
| Step 4. Translate. | Together the husband and wife earn $110,000. | |
| Restate the problem in one sentence with all the important information. | ||
| Translate into an equation. | ||
| Step 5. Solve the equation. | h + 2h − 16,000 = 110,000 | |
| Combine like terms. | 3h − 16,000 = 110,000 | |
| Add 16,000 to both sides and simplify. | 3h = 126,000 | |
| Divide each side by 3. | h = 42,000 | |
| $42,000 amount husband earns | ||
| 2h − 16,000 amount wife earns | ||
| 2(42,000) − 16,000 | ||
| 84,000 − 16,000 | ||
| 68,000 | ||
| Step 6. Check. | ||
| If the wife earns $68,000 and the husband earns $42,000 is the total $110,000? Yes! | ||
| Step 7. Answer the question. | The husband earns $42,000 a year. |
The book's Try It right after this example: same idea, new numbers. Only the answer is given.
According to the National Automobile Dealers Association, the average cost of a car in 2014 was $28,500. This was $1,500 less than 6 times the cost in 1975. What was the average cost of a car in 1975?
How did it go?