Example 9.12 from Prealgebra, 9.2 Solve Money Applications
Maria has in quarters and pennies in her wallet. She has twice as many pennies as quarters. How many coins of each type does she have?
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
Step 1. Read the problem.
| Type | |||
|---|---|---|---|
| Quarters | |||
| Pennies | |||
Step 2. Identify what you are looking for.
Step 3. Name: Represent the number of quarters and pennies using variables.
| Type | |||
|---|---|---|---|
| Quarters | |||
| Pennies | |||
Multiply the ‘number’ and the ‘value’ to get the ‘total value’ of each type of coin.
| Type | |||
|---|---|---|---|
| Quarters | |||
| Pennies | |||
Step 4. Translate. Write the equation by adding the 'total value’ of all the types of coins.
Step 5. Solve the equation.
| Write the equation. | |
| Multiply. | |
| Combine like terms. | |
| Divide by 0.27. | |
| The number of pennies is 2q. |
Step 6. Check the answer in the problem.
Maria has quarters and pennies. Does this make
Step 7. Answer the question. Maria has nine quarters and eighteen pennies.
The book's Try It right after this example: same idea, new numbers. Only the answer is given.
Sumanta has in nickels and dimes in her desk drawer. She has twice as many nickels as dimes. How many coins of each type does she have?
How did it go?