Carregando…
Exemplo 9.44 de Prealgebra, 9.5 Solve Geometry Applications: Circles and Irregular Figures
Solve Geometry Applications: Circles and Irregular Figures: exemplo 9.44
Problema e solução em inglês, como no livro original.
Find the area of the shaded region.
Resolva no papel primeiro. Depois abra a solução um passo de cada vez e pare assim que conseguir terminar sozinho.
Solução
The given figure is irregular, but we can break it into two rectangles. The area of the shaded region will be the sum of the areas of both rectangles.
The blue rectangle has a width of and a length of The red rectangle has a width of but its length is not labeled. The right side of the figure is the length of the red rectangle plus the length of the blue rectangle. Since the right side of the blue rectangle is units long, the length of the red rectangle must be units.
The area of the figure is square units.
Is there another way to split this figure into two rectangles? Try it, and make sure you get the same area.
Sua vez
O Try It do livro logo depois deste exemplo: mesma ideia, outros números. Só a resposta é dada.
Find the area of each shaded region:
Como foi?