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Example 9.8 from Prealgebra, 9.1 Use a Problem Solving Strategy
One number is ten more than twice another. Their sum is one. Find the numbers.
Work it out on paper first. Then open the solution one step at a time, and stop as soon as you can finish on your own.
| Step 1. Read the problem. | ||
| Step 2. Identify what you are looking for. | two numbers | |
| Step 3. Name. Choose a variable. One number is ten more than twice another. |
Let x = 1st number 2x + 10 = 2nd number |
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| Step 4. Translate. Restate as one sentence. | Their sum is one. | |
| Translate into an equation | ||
| Step 5. Solve the equation. | ||
| Combine like terms. | ||
| Subtract 10 from each side. | ||
| Divide each side by 3 to get the first number. | ||
| Substitute to get the second number. | ||
| Step 6. Check. | ||
| Is 4 ten more than twice −3? Is their sum 1? |
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| Step 7. Answer the question. | The numbers are −3 and 4. |
The book's Try It right after this example: same idea, new numbers. Only the answer is given.
One number is eight more than twice another. Their sum is negative four. Find the numbers.
How did it go?