Contents

Preface
1What is Physics?
2Motion in One Dimension
3Acceleration
4Forces and Newton’s Laws of Motion
5Motion in Two Dimensions
6Circular and Rotational Motion
7Newton's Law of Gravitation
8Momentum
9Work, Energy, and Simple Machines
10Special Relativity
11Thermal Energy, Heat, and Work
12Thermodynamics
13Waves and Their Properties
14Sound
15Light
16Mirrors and Lenses
- Introduction
- 16.1Reflection
- 16.2Refraction
- 16.3Lenses
- Key Terms
- Section Summary
- Key Equations
- Chapter Review
17Diffraction and Interference
18Static Electricity
19Electrical Circuits
20Magnetism
21The Quantum Nature of Light
22The Atom
23Particle Physics
- Introduction
- 23.1The Four Fundamental Forces
- 23.2Quarks
- 23.3The Unification of Forces
- Key Terms
- Section Summary
- Chapter Review
AReference Tables
Index

Understanding Diffraction and Interference

Section Learning Objectives

By the end of this section, you will be able to do the following:

Explain wave behavior of light, including diffraction and interference, including the role of constructive and destructive interference in Young’s single-slit and double-slit experiments
Perform calculations involving diffraction and interference, in particular the wavelength of light using data from a two-slit interference pattern

Section Key Terms

diffraction

Huygens’s principle

monochromatic

wavefront

Diffraction and Interference

We know that visible light is the type of electromagnetic wave to which our eyes responds. As we have seen previously, light obeys the equation

c = f λ, c = f λ,

where $c = 3.00 \times 10^{8} c = 3.00$ m/s is the speed of light in vacuum, f is the frequency of the electromagnetic wave in Hz (or s^–1), and $λ λ$ is its wavelength in m. The range of visible wavelengths is approximately 380 to 750 nm. As is true for all waves, light travels in straight lines and acts like a ray when it interacts with objects several times as large as its wavelength. However, when it interacts with smaller objects, it displays its wave characteristics prominently. Interference is the identifying behavior of a wave.

In Figure 17.2, both the ray and wave characteristics of light can be seen. The laser beam emitted by the observatory represents ray behavior, as it travels in a straight line. Passing a pure, one-wavelength beam through vertical slits with a width close to the wavelength of the beam reveals the wave character of light. Here we see the beam spreading out horizontally into a pattern of bright and dark regions that are caused by systematic constructive and destructive interference. As it is characteristic of wave behavior, interference is observed for water waves, sound waves, and light waves.

(a) Photo of a laser beam directed vertically from an observatory into a night sky. (b) Photo of a horizontal line of about twenty closely spaced red dots. The five dots in the center are much brighter than the others.

Figure 17.2 (a) The light beam emitted by a laser at the Paranal Observatory (part of the European Southern Observatory in Chile) acts like a ray, traveling in a straight line. (credit: Yuri Beletsky, European Southern Observatory) (b) A laser beam passing through a grid of vertical slits produces an interference pattern—characteristic of a wave. (credit: Shim’on and Slava Rybka, Wikimedia Commons)

That interference is a characteristic of energy propagation by waves is demonstrated more convincingly by water waves. Figure 17.3 shows water waves passing through gaps between some rocks. You can easily see that the gaps are similar in width to the wavelength of the waves and that this causes an interference pattern as the waves pass beyond the gaps. A cross-section across the waves in the foreground would show the crests and troughs characteristic of an interference pattern.

Drawing of two groups of rocks on a beach. Waves from the top of figure produce three sets of curved wavefronts that expand outward as they pass through gaps between the rocks.

Figure 17.3 Incoming waves (at the top of the picture) pass through the gaps in the rocks and create an interference pattern (in the foreground).

Light has wave characteristics in various media as well as in a vacuum. When light goes from a vacuum to some medium, such as water, its speed and wavelength change, but its frequency, f, remains the same. The speed of light in a medium is $v = c / n v = c / n$ , where n is its index of refraction. If you divide both sides of the equation $c = f λ c = f λ$ by n, you get $c / n = v = f λ / n c / n = v = f λ / n$ . Therefore, $v = f λ_{n} v = f λ_{n}$ , where $λ_{n} λ_{n}$ is the wavelength in a medium, and

λ_{n} = \frac{λ}{n}, λ_{n} = \frac{λ}{n},

where $λ λ$ is the wavelength in vacuum and n is the medium’s index of refraction. It follows that the wavelength of light is smaller in any medium than it is in vacuum. In water, for example, which has n = 1.333, the range of visible wavelengths is (380 nm)/1.333 to (760 nm)/1.333, or $λ_{n} = λ_{n} =$ 285–570 nm. Although wavelengths change while traveling from one medium to another, colors do not, since colors are associated with frequency.

The Dutch scientist Christiaan Huygens (1629–1695) developed a useful technique for determining in detail how and where waves propagate. He used wavefronts, which are the points on a wave’s surface that share the same, constant phase (such as all the points that make up the crest of a water wave). Huygens’s principle states, “Every point on a wavefront is a source of wavelets that spread out in the forward direction at the same speed as the wave itself. The new wavefront is a line tangent to all of the wavelets.”

Figure 17.4 shows how Huygens’s principle is applied. A wavefront is the long edge that moves; for example, the crest or the trough. Each point on the wavefront emits a semicircular wave that moves at the propagation speed v. These are drawn later at a time, t, so that they have moved a distance $s = v t s = v t$ . The new wavefront is a line tangent to the wavelets and is where the wave is located at time t. Huygens’s principle works for all types of waves, including water waves, sound waves, and light waves. It will be useful not only in describing how light waves propagate, but also in how they interfere.

Drawing with vertical lines labeled “old wavefront” (on the left) and “new wavefront” (on the right). Semicircular wavelets expand to the right from points on the old wavefront. The new wavefront is the tangent to those circles. The two wavefronts are separated by a distance s. A formula states “s is the product of the wave speed v and time t.”

Figure 17.4 Huygens’s principle applied to a straight wavefront. Each point on the wavefront emits a semicircular wavelet that moves a distance

s = v t s = v t

. The new wavefront is a line tangent to the wavelets.

What happens when a wave passes through an opening, such as light shining through an open door into a dark room? For light, you expect to see a sharp shadow of the doorway on the floor of the room, and you expect no light to bend around corners into other parts of the room. When sound passes through a door, you hear it everywhere in the room and, thus, you understand that sound spreads out when passing through such an opening. What is the difference between the behavior of sound waves and light waves in this case? The answer is that the wavelengths that make up the light are very short, so that the light acts like a ray. Sound has wavelengths on the order of the size of the door, and so it bends around corners.

If light passes through smaller openings, often called slits, you can use Huygens’s principle to show that light bends as sound does (see Figure 17.5). The bending of a wave around the edges of an opening or an obstacle is called diffraction. Diffraction is a wave characteristic that occurs for all types of waves. If diffraction is observed for a phenomenon, it is evidence that the phenomenon is produced by waves. Thus, the horizontal diffraction of the laser beam after it passes through slits in Figure 17.2 is evidence that light has the properties of a wave.

Three drawings of evenly spaced parallel vertical lines represent straight wavefronts moving to the right and passing through three openings in a barrier. The drawing on the left shows vertical straight lines to the left of a wide opening, overlaid with horizontal arrows pointing to the right, and three parallel lines to the right of the opening. The lines to the right of the opening are roughly the same length as the opening. The upper and lower ends of the lines to the right are swept to the left, forming small curves, but the lines are mostly straight. The small curves at the top are overlaid with an arrow pointing to the right and slightly upward; the small curves at the bottom are overlaid with an arrow pointing to the right and slightly downward. The drawing in the middle shows vertical straight lines to the left of a narrower opening and three parallel lines to the right of the opening. The lines to the right of the opening are roughly the same length as the opening, which is smaller than the opening in the drawing on the left. The upper and lower ends of the lines to the right of the opening are swept to the left, forming small curves, but the lines are mostly straight. The drawing on the right shows vertical straight lines to the left of a very narrow opening, overlaid with one horizontal arrows pointing to the right, and three concentric circular arcs to the right of the opening.

Figure 17.5 Huygens’s principle applied to a straight wavefront striking an opening. The edges of the wavefront bend after passing through the opening, a process called diffraction. The amount of bending is more extreme for a small opening, consistent with the fact that wave characteristics are most noticeable for interactions with objects about the same size as the wavelength.

Once again, water waves present a familiar example of a wave phenomenon that is easy to observe and understand, as shown in Figure 17.6.

Drawing of ocean waves passing through a narrow gap in a reef. The waves form semicircular wavelets on the beach, which are centered on the gap in the reef.

Figure 17.6 Ocean waves pass through an opening in a reef, resulting in a diffraction pattern. Diffraction occurs because the opening is similar in width to the wavelength of the waves.

Watch Physics

Single-Slit Interference

This video works through the math needed to predict diffraction patterns that are caused by single-slit interference.

Access multimedia content Open the interactiveOpen the interactive

Which values of m denote the location of destructive interference in a single-slit diffraction pattern?

whole integers, excluding zero
whole integers
real numbers excluding zero
real numbers

The fact that Huygens’s principle worked was not considered enough evidence to prove that light is a wave. People were also reluctant to accept light’s wave nature because it contradicted the ideas of Isaac Newton, who was still held in high esteem. The acceptance of the wave character of light came after 1801, when the English physicist and physician Thomas Young (1773–1829) did his now-classic double-slit experiment (see Figure 17.7).

Drawing of a beam of light diffracted by two slits. Two arrows pointing upward and to the right have their points at the vertical slits. A pattern is on a second screen, upward and to the right, consists of about 14 vertical bright bands that are the same height as the slits but have a horizontal spacing closer than the slits.

Figure 17.7 Young’s double-slit experiment. Here, light of a single wavelength passes through a pair of vertical slits and produces a diffraction pattern on the screen—numerous vertical light and dark lines that are spread out horizontally. Without diffraction and interference, the light would simply make two lines on the screen.

When light passes through narrow slits, it is diffracted into semicircular waves, as shown in Figure 17.8 (a). Pure constructive interference occurs where the waves line up crest to crest or trough to trough. Pure destructive interference occurs where they line up crest to trough. The light must fall on a screen and be scattered into our eyes for the pattern to be visible. An analogous pattern for water waves is shown in Figure 17.8 (b). Note that regions of constructive and destructive interference move out from the slits at well-defined angles to the original beam. Those angles depend on wavelength and the distance between the slits, as you will see below.

(a) Drawing of vertical lines to the left of a screen with two slits, labeled “S-one” and “S-two.” Vertical lines on the left are labeled “Wavefront.” They are overlaid with arrows labeled “Rays.” Two sets of overlapping circular arcs expand outward from the two slits to a screen at the right. The screen on the right is labeled “Screen.” Each set consists of alternating solid and dotted lines. A line from the point on the screen midway between the two slits extends to the center of the screen on the right, toward a label “Max.” Above the Max are other labels on the screen. They are “Min,” “Max,” and another “Min.” Lines run from the screen at the left to those labels at the right. The screen at the right also has a symmetrical arrangement of lines and labels “Min” and “Max” below the central Max. (b) Drawing of semicircles waves moving to the right from two points. (c) A vertical band of closely spaced horizontal red bands. There are about nine bands in the center with a dark space below, four bands that are somewhat dimmer, another dark space, and a still dimmer group of three bands. A symmetrical pattern of red bands and dark spaces and minima appears above the central maximum.

Figure 17.8 Double slits produce two sources of waves that interfere. (a) Light spreads out (diffracts) from each slit, because the slits are narrow. The waves overlap and interfere constructively (bright lines) and destructively (dark regions). You can only see the effect if the light falls onto a screen and is scattered into your eyes. (b) The double-slit interference pattern for water waves is nearly identical to that for light. Wave action is greatest in regions of constructive interference and least in regions of destructive interference. (c) When light that has passed through double slits falls on a screen, we see a pattern such as this.

Virtual Physics

Wave Interference

This simulation demonstrates most of the wave phenomena discussed in this section. First, observe interference between two sources of electromagnetic radiation without adding slits. See how water waves, sound, and light all show interference patterns. Stay with light waves and use only one source. Create diffraction patterns with one slit and then with two. You may have to adjust slit width to see the pattern.

Visually compare the slit width to the wavelength. When do you get the best-defined diffraction pattern?

when the slit width is larger than the wavelength
when the slit width is smaller than the wavelength
when the slit width is comparable to the wavelength
when the slit width is infinite

Calculations Involving Diffraction and Interference

The fact that the wavelength of light of one color, or monochromatic light, can be calculated from its two-slit diffraction pattern in Young’s experiments supports the conclusion that light has wave properties. To understand the basis of such calculations, consider how two waves travel from the slits to the screen. Each slit is a different distance from a given point on the screen. Thus different numbers of wavelengths fit into each path. Waves start out from the slits in phase (crest to crest), but they will end up out of phase (crest to trough) at the screen if the paths differ in length by half a wavelength, interfering destructively. If the paths differ by a whole wavelength, then the waves arrive in phase (crest to crest) at the screen, interfering constructively. More generally, if the paths taken by the two waves differ by any half-integral number of wavelengths $(\frac{1}{2} λ, \frac{3}{2} λ, \frac{5}{2} λ, etc .) (\frac{1}{2} λ, \frac{3}{2} λ, \frac{5}{2} λ, etc .)$ , then destructive interference occurs. Similarly, if the paths taken by the two waves differ by any integral number of wavelengths $(λ, 2 λ, 3 λ, etc .) (λ, 2 λ, 3 λ, etc .)$ , then constructive interference occurs.

Figure 17.9 shows how to determine the path-length difference for waves traveling from two slits to a common point on a screen. If the screen is a large distance away compared with the distance between the slits, then the angle $θ θ$ between the path and a line from the slits perpendicular to the screen (see the figure) is nearly the same for each path. That approximation and simple trigonometry show the length difference, $Δ L Δ L$ , to be $d \sin θ d \sin θ$ , where d is the distance between the slits,

Δ L = d \sin θ . Δ L = d \sin θ .

To obtain constructive interference for a double slit, the path-length difference must be an integral multiple of the wavelength, or

d \sin θ = m λ, for m = 0, 1, - 1, 2, - 2, \dots (constructive). d \sin θ = m λ, for m = 0, 1, - 1, 2, - 2, \dots (constructive).

Similarly, to obtain destructive interference for a double slit, the path-length difference must be a half-integral multiple of the wavelength, or

d \sin θ = (m + ½) λ, for m = 0, 1, - 1, 2, - 2, \dots (destructive). d \sin θ = (m + ½) λ, for m = 0, 1, - 1, 2, - 2, \dots (destructive).

The number m is the order of the interference. For example, m = 4 is fourth-order interference.

Drawing showing two vertical screens. The screen the left has two slits labeled “S-one” and “S-two.” The screen on the right is labeled “Screen.” Two arrows labeled “L-one” and “L-two” point upward and to the right. They begin at their respective slits and meet at the screen on the right. The distance between slits S-one and S-two is labeled “d,” and that distance is the hypotenuse of a right triangle. The shorter leg of the right triangle is labeled “delta-L.” It extends from the lower slit, S-two, upward and to the right along the arrow leaving slit S-two. The longer leg of the triangle is a line perpendicular to the two light rays and having one end at the upper slit, S-one. The angle of the vertex of the triangle located at slit S-one is labeled “theta.” A formula states “the distance delta-L as the product of the distance d and the sine of the angle theta.”

Figure 17.9 The paths from each slit to a common point on the screen differ by an amount

d \sin θ d \sin θ

, assuming the distance to the screen is much greater than the distance between the slits (not to scale here).

Figure 17.10 shows how the intensity of the bands of constructive interference decreases with increasing angle.

Two drawings showing diffraction by two slits. The first drawing, on the left shows, two vertical screens. The screen on the left has two slits separated by a vertical distance labeled “d.” A second screen is shown a to the right of the screen with the slits, separated by a horizontal distance labeled “x.” The vertical screen at the right shows a graph of a series of peaks and valleys that grow horizontally to the left. The tallest peak is at the center, with valleys and successively smaller peaks arranged symmetrically above and below it. A horizontal line runs from the point midway between the slits in the screen at the left through the central peak of the graph. A dotted line runs from that midway point through the first peak above the center. A second dotted line runs from the midway point through the second maximum. Those dotted lines make angles labeled “theta-one” and “theta-two” with the horizontal line. The peaks above the center are distances labeled “y-one” and “y-two” above the center. The second drawing, on the right shows, a vertical array of horizontal bright bands on a black background. They are aligned with the peaks of the graph in the first drawing. The bands are all of the same length but are of differing widths. The widest band is in the center and successively narrower bands are arranged symmetrically above and below it.

Figure 17.10 The interference pattern for a double slit has an intensity that falls off with angle. The photograph shows multiple bright and dark lines, or fringes, formed by light passing through a double slit.

Light passing through a single slit forms a diffraction pattern somewhat different from that formed by double slits. Figure 17.11 shows a single-slit diffraction pattern. Note that the central maximum is larger than those on either side, and that the intensity decreases rapidly on either side.

(a) A drawing of a single slit in a vertical screen. The slit has width labeled “D.” (b) Drawing showing two patterns. On the left, a graph has a series of peaks and valleys that grow horizontally to the left. The central peak is largest, with much smaller peaks arranged symmetrically above and below it. To the right of the graph, a second pattern is a vertical array of horizontal bright bands separated by dark bands. They are aligned with the peaks of the graph in the first drawing. The bands are all of the same length but are of differing widths. The widest band is in the center and narrower bands are arranged symmetrically above and below it. (c) A version of the graph of the pattern in drawing (b) rotated so that the peaks grow upward from a horizontal axis. The height of the peaks is labeled “Intensity,” and the central peak is much higher and wider than the other peaks. The horizontal axis is labeled as the “sine of theta,” and the largest, central peak is located at a point on the horizontal axis labeled “zero.” Three valleys are located to the right of the central maximum at distances that are labeled “lambda divided by D,” “two lambda divided by D,” and “three lambda divided by D.” Three other valleys are located to the left of the center at distances that are labeled “negative lambda divided by D,” “negative two lambda divided by D,” and “negative three lambda divided by D.”

Figure 17.11 (a) Single-slit diffraction pattern. Monochromatic light passing through a single slit produces a central maximum and many smaller and dimmer maxima on either side. The central maximum is six times higher than shown. (b) The drawing shows the bright central maximum and dimmer and thinner maxima on either side. (c) The location of the minima are shown in terms of

λ λ

and D.

The analysis of single-slit diffraction is illustrated in Figure 17.12. Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel. That approximation allows a series of trigonometric operations that result in the equations for the minima produced by destructive interference.

D \sin θ = m λ D \sin θ = m λ

\frac{D y}{L} = m λ \frac{D y}{L} = m λ

When rays travel straight ahead, they remain in phase and a central maximum is obtained. However, when rays travel at an angle $θ θ$ relative to the original direction of the beam, each ray travels a different distance to the screen, and they can arrive in or out of phase. Thus, a ray from the center travels a distance $λ / 2 λ / 2$ farther than the ray from the top edge of the slit, they arrive out of phase, and they interfere destructively. Similarly, for every ray between the top and the center of the slit, there is a ray between the center and the bottom of the slit that travels a distance $λ / 2 λ / 2$ farther to the common point on the screen, and so interferes destructively. Symmetrically, there will be another minimum at the same angle below the direct ray.

Drawing entitled “Destructive interference.” It shows two screens, one on the left having a slit with width labeled “D.” The distance from the slit to the screen on the right is labeled “L.” It is represented as a dashed line that runs through the center of the slit and is perpendicular to both screens. A solid line extends upward and to the right from the center of the slit to strike the screen on the right. That line forms an angle labeled “theta” with the horizontal dashed line. A second solid line, from the top of the slit, extends upward and to the right to strike the same point as the first solid line. That point is a distance labeled “y” above the horizontal dashed line. A formula states that “D times the sine of the angle theta is equal to m times the wavelength lambda.” A second formula states that “D times y divided by L is equal to m times lambda.”

Figure 17.12 Equations for a single-slit diffraction pattern, where λ is the wavelength of light, D is the slit width,

θ θ

is the angle between a line from the slit to a minimum and a line perpendicular to the screen, L is the distance from the slit to the screen, y is the distance from the center of the pattern to the minimum, and m is a nonzero integer indicating the order of the minimum.

Below we summarize the equations needed for the calculations to follow.

The speed of light in a vacuum, c, the wavelength of the light, $λ λ$ , and its frequency, f, are related as follows.

c = f λ c = f λ

The wavelength of light in a medium, $λ_{n} λ_{n}$ , compared to its wavelength in a vacuum, $λ λ$ , is given by

λ_{n} = \frac{λ}{n} . λ_{n} = \frac{λ}{n} .

17.1

To calculate the positions of constructive interference for a double slit, the path-length difference must be an integral multiple, m, of the wavelength. $λ λ$

d \sin θ = m λ, for m = 0, 1, - 1, 2, - 2, \dots (constructive), d \sin θ = m λ, for m = 0, 1, - 1, 2, - 2, \dots (constructive),

where d is the distance between the slits and $θ θ$ is the angle between a line from the slits to the maximum and a line perpendicular to the barrier in which the slits are located. To calculate the positions of destructive interference for a double slit, the path-length difference must be a half-integral multiple of the wavelength:

d \sin θ = (m + ½) λ, for m = 0, 1, - 1, 2, - 2, \dots (destructive). d \sin θ = (m + ½) λ, for m = 0, 1, - 1, 2, - 2, \dots (destructive).

For a single-slit diffraction pattern, the width of the slit, D, the distance of the first (m = 1) destructive interference minimum, y, the distance from the slit to the screen, L, and the wavelength, $λ λ$ , are given by

\frac{D y}{L} = λ . \frac{D y}{L} = λ .

Also, for single-slit diffraction,

D \sin θ = m λ, D \sin θ = m λ,

where $θ θ$ is the angle between a line from the slit to the minimum and a line perpendicular to the screen, and m is the order of the minimum.

Worked Example

Two-Slit Interference

Suppose you pass light from a He-Ne laser through two slits separated by 0.0100 mm, and you find that the third bright line on a screen is formed at an angle of 10.95º relative to the incident beam. What is the wavelength of the light?

Strategy

The third bright line is due to third-order constructive interference, which means that m = 3. You are given d = 0.0100 mm and $θ θ$ = 10.95º. The wavelength can thus be found using the equation $d \sin θ = m λ d \sin θ = m λ$ for constructive interference.

Show solution

Solution

The equation is $d \sin θ = m λ d \sin θ = m λ$ . Solving for the wavelength, $λ λ$ , gives

λ = \frac{d \sin θ}{m} . λ = \frac{d \sin θ}{m} .

17.2

Substituting known values yields

λ = \frac{(0.0100 mm) (\sin 10.95°)}{3} = 6.33 \times 10^{−4} mm = 633 nm . λ = \frac{(0.0100) (\sin 10.95°)}{3} = 6.33

17.3

Discussion

To three digits, 633 nm is the wavelength of light emitted by the common He-Ne laser. Not by coincidence, this red color is similar to that emitted by neon lights. More important, however, is the fact that interference patterns can be used to measure wavelength. Young did that for visible wavelengths. His analytical technique is still widely used to measure electromagnetic spectra. For a given order, the angle for constructive interference increases with $λ λ$ , so spectra (measurements of intensity versus wavelength) can be obtained.

Worked Example

Single-Slit Diffraction

Visible light of wavelength 550 nm falls on a single slit and produces its second diffraction minimum at an angle of 45.0° relative to the incident direction of the light. What is the width of the slit?

Strategy

From the given information, and assuming the screen is far away from the slit, you can use the equation $D \sin θ = m λ D \sin θ = m λ$ to find D.

Show solution

Solution

Quantities given are $λ λ$ = 550 nm, m = 2, and $θ_{2} θ_{2}$ = 45.0°. Solving the equation $D \sin θ = m λ D \sin θ = m λ$ for D and substituting known values gives

D = \frac{m λ}{sin θ} = \frac{2 (550 nm)}{sin 45.0°} = 1.56 \times 10^{−6} m. D = \frac{m λ}{sin θ} = \frac{2 (550}{sin 45.0°} = 1.56

17.4

Discussion

You see that the slit is narrow (it is only a few times greater than the wavelength of light). That is consistent with the fact that light must interact with an object comparable in size to its wavelength in order to exhibit significant wave effects, such as this single-slit diffraction pattern.

Practice Problems

1 .

Monochromatic light from a laser passes through two slits separated by

0.00500 mm

. The third bright line on a screen is formed at an angle of

{18.0}^{\circ}

relative to the incident beam. What is the wavelength of the light?

$51.5 nm$
$77.3 nm$
$515 nm$
$773 nm$

What is the width of a single slit through which 610-nm orange light passes to form a first diffraction minimum at an angle of 30.0°?

0.863 µm
0.704 µm
0.610 µm
1.22 µm

Check Your Understanding

3 .

Which aspect of a beam of monochromatic light changes when it passes from a vacuum into water, and how does it change?

The wavelength first decreases and then increases.
The wavelength first increases and then decreases.
The wavelength increases.
The wavelength decreases.

4 .

Go outside in the sunlight and observe your shadow. It has fuzzy edges, even if you do not. Is this a diffraction effect? Explain.

This is a diffraction effect. Your whole body acts as the origin for a new wavefront.
This is a diffraction effect. Every point on the edge of your shadow acts as the origin for a new wavefront.
This is a refraction effect. Your whole body acts as the origin for a new wavefront.
This is a refraction effect. Every point on the edge of your shadow acts as the origin for a new wavefront.

5 .

Which aspect of monochromatic green light changes when it passes from a vacuum into diamond, and how does it change?

The wavelength first decreases and then increases.
The wavelength first increases and then decreases.
The wavelength increases.
The wavelength decreases.